Chapter 5 · Question 4

State the formula for the sum of first nn terms of an AP. Find the sum of first 20 natural numbers.

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Answer

Direct Answer

The sum is Sn=n2[2a+(n1)d]S_n=\frac n2[2a+(n-1)d] or Sn=n2(a+l)S_n=\frac n2(a+l). For natural numbers, a=1a=1, d=1d=1, n=20n=20, so S20=202(1+20)=210S_{20}=\frac{20}{2}(1+20)=210.

Simple Explanation

Use Sn=n(a+l)/2S_n=n(a+l)/2. The first 20 natural numbers add to 210210.

Exam-Ready Structure

For an AP, Sn=n2[2a+(n1)d]S_n=\frac n2[2a+(n-1)d]. If the last term ll is known, Sn=n2(a+l)S_n=\frac n2(a+l). For 1,2,3,,201,2,3,\ldots,20, a=1a=1, l=20l=20, n=20n=20. Therefore S20=202(1+20)=10×21=210S_{20}=\frac{20}{2}(1+20)=10\times21=210.

Key Points

  • The sum is Sn=n2[2a+(n1)d]S_n=\frac n2[2a+(n-1)d] or Sn=n2(a+l)S_n=\frac n2(a+l).