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Chapter 5 · Question 5

Reena starts with a monthly salary of ₹8000 and gets an annual increment of ₹500. What will be her salary in the 10th year?

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Q5

Reena starts with a monthly salary of ₹8000 and gets an annual increment of ₹500. What will be her salary in the 10th year?

Answer Revealed

Direct Answer:

This is an AP with

a=8000

,

d=500

, and

n=10

.

a_{10}=8000+9\times500=12500

.

Simple Explanation

Each year adds ₹500. In the 10th year, there have been 9 increments, so salary is ₹12500.

Exam-Ready Structure

The salary sequence is

8000,8500,9000,\ldots

, an AP. Use

a_n=a+(n-1)d

. For

n=10

,

a_{10}=8000+(10-1)500=8000+4500=12500

.

Key Points

This is an AP with $a=8000$ , $d=500$ , and $n=10$ .
Use the NCERT formula or theorem carefully.
Write units and final conclusion where applicable.

Related Questions

Find the sum of the first 15 terms of the AP $5,8,11,\ldots$ .

What is an arithmetic progression? Find the common difference of $45,43,41,39,\ldots$ .

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