Chapter 5 · Question 2

State the formula for the nnth term of an AP and use it to find the 20th term of 3,7,11,15,3,7,11,15,\ldots.

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Q2

State the formula for the nnth term of an AP and use it to find the 20th term of 3,7,11,15,3,7,11,15,\ldots.

Answer Revealed
Direct Answer:
For an AP with first term aa and common difference dd, an=a+(n1)da_n=a+(n-1)d. Here a=3a=3, d=4d=4, so a20=3+19×4=79a_{20}=3+19\times4=79.

Simple Explanation

Use an=a+(n1)da_n=a+(n-1)d. The 20th term is 7979.

Exam-Ready Structure

The first term is a=3a=3 and common difference d=73=4d=7-3=4. Thus an=a+(n1)da_n=a+(n-1)d. For n=20n=20, a20=3+(201)4=3+76=79a_{20}=3+(20-1)4=3+76=79.

Key Points

  • For an AP with first term aa and common difference dd, an=a+(n1)da_n=a+(n-1)d.
  • Use the NCERT formula or theorem carefully.
  • Write units and final conclusion where applicable.