Chapter 1 · Question 5

Balance the following equation using the hit-and-trial method and write the final balanced equation with state symbols: Fe+H2OFe3O4+H2\text{Fe} + \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2. Why is H₂O written with the state symbol (g) in the balanced form?

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Q5

Balance the following equation using the hit-and-trial method and write the final balanced equation with state symbols: Fe+H2OFe3O4+H2\text{Fe} + \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2. Why is H₂O written with the state symbol (g) in the balanced form?

Answer Revealed
Direct Answer:
Using the hit-and-trial method: Initial skeletal equation Fe+H2OFe3O4+H2\text{Fe} + \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2. Step I — balance oxygen: add coefficient 4 to H₂O → Fe+4H2OFe3O4+H2\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2. Step II — balance hydrogen: add coefficient 4 to H₂ → Fe+4H2OFe3O4+4H2\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4\text{H}_2. Step III — balance iron: add coefficient 3 to Fe → 3Fe+4H2OFe3O4+4H23\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4\text{H}_2. Final balanced equation with state symbols: 3Fe(s)+4H2O(g)Fe3O4(s)+4H2(g)3\text{Fe(s)} + 4\text{H}_2\text{O(g)} \rightarrow \text{Fe}_3\text{O}_4\text{(s)} + 4\text{H}_2\text{(g)}. H₂O is written as (g) because steam (water vapour) is used in this reaction.

Simple Explanation

Walk through the balancing step by step: Start with Fe+H2OFe3O4+H2\text{Fe} + \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2. There are 4 O on right vs 1 on left, so put 4 before H₂O. Now hydrogen has 8 atoms on left vs 2 on right, so put 4 before H₂. Now Fe is 1 on left vs 3 on right, so put 3 before Fe. The balanced equation: 3Fe+4H2OFe3O4+4H23\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4\text{H}_2. The state symbols are (s) for solid metals and (g) for gases — the water is steam (g) in this reaction.

Exam-Ready Structure

The systematic step-by-step balancing of Fe+H2OFe3O4+H2\text{Fe} + \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2 illustrates the hit-and-trial method: 1. List initial atom counts: LHS has Fe=1, H=2, O=1. RHS has Fe=3, H=2, O=4. Oxygen and iron are unbalanced. 2. Start with the compound having the maximum number of atoms — Fe3O4\text{Fe}_3\text{O}_4 on the product side has 4 oxygen atoms. 3. To balance oxygen, multiply H2O\text{H}_2\text{O} by 4: Fe+4H2OFe3O4+H2\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2. Now LHS: O=4 (balanced), H=8. 4. To balance hydrogen (8 on LHS, 2 on RHS), multiply H2\text{H}_2 by 4: Fe+4H2OFe3O4+4H2\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4\text{H}_2. Now H=8 on both sides (balanced). 5. To balance iron (1 on LHS, 3 on RHS), multiply Fe by 3: 3Fe+4H2OFe3O4+4H23\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4\text{H}_2. 6. Final check — LHS: Fe=3, H=8, O=4. RHS: Fe=3, H=8, O=4. Balanced. 7. State symbols — iron is a solid metal (s), steam is gaseous water (g), Fe3O4\text{Fe}_3\text{O}_4 (magnetite) is a solid (s), and hydrogen is a gas (g). The final form: 3Fe(s)+4H2O(g)Fe3O4(s)+4H2(g)3\text{Fe(s)} + 4\text{H}_2\text{O(g)} \rightarrow \text{Fe}_3\text{O}_4\text{(s)} + 4\text{H}_2\text{(g)}. H₂O is written as (g) because this reaction uses steam. This notation makes the equation more informative by specifying the condition of each reactant and product.

Key Points

  • Step-wise approach: balance oxygen first (multiply H₂O by 4), then hydrogen (multiply H₂ by 4), then iron (multiply Fe by 3)
  • Always start with the compound containing the most atoms (Fe3O4\text{Fe}_3\text{O}_4 has 7 atoms)
  • State symbols: (s) = solid, (l) = liquid, (g) = gas, (aq) = aqueous solution
  • Final: 3Fe(s)+4H2O(g)Fe3O4(s)+4H2(g)3\text{Fe(s)} + 4\text{H}_2\text{O(g)} \rightarrow \text{Fe}_3\text{O}_4\text{(s)} + 4\text{H}_2\text{(g)}
  • H2O\text{H}_2\text{O} is (g) because steam, not liquid water, is used in this reaction

Common Mistakes

  • Changing the subscripts within Fe3O4\text{Fe}_3\text{O}_4 or H2O\text{H}_2\text{O} to balance (only coefficients can be changed)
  • Writing H2O(l)\text{H}_2\text{O(l)} for this reaction — the reaction uses steam, so the state symbol must be (g)