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Chapter 4 · Question 5

Find the nature of roots of $2x^2-4x+3=0$ .

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Answer

Direct Answer

Here

a=2

,

b=-4

,

c=3

. Discriminant

D=b^2-4ac=16-24=-8<0

. Therefore the equation has no real roots.

Simple Explanation

Calculate

D

. Since it is negative, there are no real roots.

Exam-Ready Structure

For

2x^2-4x+3=0

,

D=(-4)^2-4(2)(3)=16-24=-8

. Since

D<0

, the roots are not real. Hence the quadratic equation has no real solution.

Key Points

Here $a=2$ , $b=-4$ , $c=3$ .

Related Questions

A rectangular hall has area $300\text{ m}^2$ and length one metre more than twice its breadth. Form the quadratic equation for its breadth.

Define a quadratic equation and identify $a$ , $b$ , and $c$ in $2x^2+x-300=0$ .

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