Chapter 3 · Question 6

State the cross-multiplication formula for solving a pair of linear equations.

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Q6

State the cross-multiplication formula for solving a pair of linear equations.

Answer Revealed
Direct Answer:
For a1x+b1y+c1=0a_1x+b_1y+c_1=0 and a2x+b2y+c2=0a_2x+b_2y+c_2=0, xb1c2b2c1=yc1a2c2a1=1a1b2a2b1\frac{x}{b_1c_2-b_2c_1}=\frac{y}{c_1a_2-c_2a_1}=\frac{1}{a_1b_2-a_2b_1}, provided a1b2a2b10a_1b_2-a_2b_1\ne0.

Simple Explanation

Cross-multiplication gives direct formulas for xx and yy when the pair has a unique solution.

Exam-Ready Structure

The method is used when a1b2a2b10a_1b_2-a_2b_1\ne0. The formula is xb1c2b2c1=yc1a2c2a1=1a1b2a2b1\frac{x}{b_1c_2-b_2c_1}=\frac{y}{c_1a_2-c_2a_1}=\frac{1}{a_1b_2-a_2b_1}. It is a compact algebraic way to solve a consistent pair with a unique solution.

Key Points

  • For a1x+b1y+c1=0a_1x+b_1y+c_1=0 and a2x+b2y+c2=0a_2x+b_2y+c_2=0, xb1c2b2c1=yc1a2c2a1=1a1b2a2b1\frac{x}{b_1c_2-b_2c_1}=\frac{y}{c_1a_2-c_2a_1}=\frac{1}{a_1b_2-a_2b_1}, provided a1b2a2b10a_1b_2-a_2b_1\ne0.
  • Use the NCERT formula or theorem carefully.
  • Write units and final conclusion where applicable.