Chapter 8 · Question 5

Prove the identity sin2A+cos2A=1\sin^2 A+\cos^2 A=1.

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Q5

Prove the identity sin2A+cos2A=1\sin^2 A+\cos^2 A=1.

Answer Revealed
Direct Answer:
In a right triangle, sinA=ph\sin A=\frac{p}{h} and cosA=bh\cos A=\frac{b}{h}. Then sin2A+cos2A=p2+b2h2=h2h2=1\sin^2A+\cos^2A=\frac{p^2+b^2}{h^2}=\frac{h^2}{h^2}=1 by Pythagoras theorem.

Simple Explanation

Square sine and cosine. The numerator becomes hypotenuse squared, so the result is 1.

Exam-Ready Structure

Let perpendicular =p=p, base =b=b, hypotenuse =h=h. Then sinA=ph\sin A=\frac ph and cosA=bh\cos A=\frac bh. Hence sin2A+cos2A=p2h2+b2h2=p2+b2h2\sin^2A+\cos^2A=\frac{p^2}{h^2}+\frac{b^2}{h^2}=\frac{p^2+b^2}{h^2}. Since p2+b2=h2p^2+b^2=h^2, the value is 11.

Key Points

  • In a right triangle, sinA=ph\sin A=\frac{p}{h} and cosA=bh\cos A=\frac{b}{h}.
  • Use the NCERT formula or theorem carefully.
  • Write units and final conclusion where applicable.