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Chapter 7 · Question 2

Find the distance between $(2,3)$ and $(6,6)$ .

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Q2

Find the distance between $(2,3)$ and $(6,6)$ .

Answer Revealed

Direct Answer:

Distance

=\sqrt{(6-2)^2+(6-3)^2}=\sqrt{16+9}=5

.

Simple Explanation

The points differ by

4

horizontally and

3

vertically, so distance is

5

.

Exam-Ready Structure

Let

A(2,3)

and

B(6,6)

. Then

AB=\sqrt{(6-2)^2+(6-3)^2}=\sqrt{4^2+3^2}=\sqrt{25}=5

.

Key Points

Distance $=\sqrt{(6-2)^2+(6-3)^2}=\sqrt{16+9}=5$ .
Use the NCERT formula or theorem carefully.
Write units and final conclusion where applicable.

Related Questions

How can the distance formula be used to test whether three points are collinear?

State the section formula for internal division.

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