Chapter 10 · Question 2

State and prove Theorem 10.1: The tangent at any point of a circle is perpendicular to the radius through the point of contact.

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Q2

State and prove Theorem 10.1: The tangent at any point of a circle is perpendicular to the radius through the point of contact.

Answer Revealed
Direct Answer:
Statement: The tangent at any point of a circle is perpendicular to the radius through the point of contact. Proof: Let OO be the centre, XYXY be the tangent at point PP, and OPOP be the radius. Take any point QQ on XYXY other than PP. Join OQOQ. Since QQ lies outside the circle, OQ>OPOQ > OP (radius). As this holds for every point on XYXY except PP, OPOP is the shortest distance from OO to the line XYXY. The shortest distance from a point to a line is the perpendicular distance. Hence, OPXYOP \perp XY.

Simple Explanation

The radius drawn to the point where a tangent touches the circle is always at a right angle (9090^\circ) to the tangent line. This is because the radius is the shortest possible line from the centre to any point on the tangent.

Exam-Ready Structure

Theorem 10.1: The tangent at any point of a circle is perpendicular to the radius through the point of contact. Given: A circle with centre OO, a tangent XYXY touching the circle at point PP. To Prove: OPXYOP \perp XY. Construction: Take a point QQ on XYXY other than PP. Join OQOQ. Proof: Since XYXY is a tangent, the point QQ must lie outside the circle (if QQ were inside the circle, XYXY would intersect the circle at two points, making it a secant, not a tangent). Therefore, OQOQ is longer than the radius OPOP: OQ>OPOQ > OP. This is true for every point QQ on line XYXY except the point PP. Thus, OPOP is the shortest distance from centre OO to the line XYXY. It is known that the shortest distance from a point to a line is the perpendicular distance. Hence, OPOP is perpendicular to XYXY, i.e., OPXYOP \perp XY. Remark: The line containing the radius through the point of contact is called the 'normal' to the circle at that point.

Key Points

  • Statement: Radius through point of contact is perpendicular to the tangent
  • Take any point Q on tangent other than P
  • Q lies outside the circle, so OQ > OP (radius)
  • OP is the shortest distance from centre to the tangent line
  • Shortest distance = perpendicular distance, so OP ⟂ XY